Mesh Analysis 2

In this lab assignment mesh current method are used in order to determine a V1 and I1.

Figure 1: DC Circuit

R1 = 6.8k , R2 = 22k , R3 = 4.7k

R4 = 10k , V1 = 5v , V2 = 3v

According to these amount of

elements I1 and V1 will calculate

theoretically. There are three

nodes and three loops in the Fig 1.



According to mesh current analysis from the Fig 1:

I1 = 0.0556 mA , I2 = - 0.322 mA , I3 = 1.058 mA

V1 = (6.8k)*(1.058-0.322) = 5.00 v & I(10k) = I2 = - 0.322 mA

V2 = (4.7k)*(I1-I2) , V2 = (4.7k)*(0.0556 - 0.322) = - 1.25 v

According to Fig 1, the amount of resistors, currents, and drop voltages were measured by a DMM:

R1 = 6.65k , R2 = 21.5k , R3 = 4.64k , R4 = 9.83k , I1 = 0.053 mA , I2 = 0.323 mA ,  I3 = 1.055 mA

V1 = 4.99 v , I(10k) = 0.323 mA , V2 (4.7k) = -1.256 v

Percent Error = [Theory - Measure) / Theory]*100%

percent error (V1) = [(5.00 - 4.99) / 5.00]*100% = 0.2%

percent error (V2) = [(1.25 - 1.256) / 1.25]*100% = 0.48%

percent error [I(10k)] = [(0.322 - 0.323) / 0.322]*100% = 0.31%

All of percent errors are so small.

Figure 2: Actual Circuit & Amount of V1